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which figure has a greater area? 10 in 7 in 6 in 8 in 9 in

Question

which figure has a greater area? 10 in 7 in 6 in 8 in 9 in

Explanation:

Step1: Calculate parallelogram area

The area formula for a parallelogram is $A = base\times height$. Here, the base is 7 in and the height is 10 in. So, $A_{1}=7\times10 = 70$ square - inches.

Step2: Calculate trapezoid area

The area formula for a trapezoid is $A=\frac{(a + b)h}{2}$, where $a$ and $b$ are the lengths of the parallel - sides and $h$ is the height. Here, $a = 6$ in, $b = 9$ in, and $h = 8$ in. Then $A_{2}=\frac{(6 + 9)\times8}{2}=\frac{15\times8}{2}=60$ square - inches.

Step3: Compare areas

Since $70>60$, the parallelogram has a greater area.

Answer:

The parallelogram has a greater area.