QUESTION IMAGE
Question
which expression is equivalent to \\( \left(\frac{x^{-6}}{x^2}\
ight)^3 \\)?
- \\( \frac{1}{x} \\)
- \\( \frac{1}{x^5} \\)
- \\( \frac{1}{x^9} \\)
- \\( \frac{1}{x^{24}} \\)
Simplify the inner fraction
$$
\frac{x^{-6}}{x^2} = x^{-6 - 2} = x^{-8}
$$
Apply the outer exponent
$$
(x^{-8})^3 = x^{-8 \cdot 3} = x^{-24}
$$
Convert to positive exponent
$$
x^{-24} = \frac{1}{x^{24}}
$$
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- (A) \(\frac{1}{x}\)
- (B) \(\frac{1}{x^5}\)
- (C) \(\frac{1}{x^9}\)
- (D) \(\frac{1}{x^{24}}\) (Correct answer)