Question

which equation can you use to evaluate \\(\log_{6} 1,296\\)?

\\(a^{6} = 1,296\\)
\\(6^{a} = 1,296\\)
\\(6a = 1,296\\)

Explanation:

⚡ Using what you learned: Understanding Logarithmic Functions

Step 1: Set up the logarithmic equation

Set the expression equal to a variable, \( a \):

$$ \log_{6}(1,296) = a $$

Step 2: Convert to exponential form

Apply the definition of a logarithm, where \(\log_{b}(x) = y\) is equivalent to \(b^y = x\):

$$ 6^a = 1,296 $$

Answer:

\( 6^a = 1,296 \) (the second option)