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Question
which equation has 3 as a solution? x + 3 = 26; 5x = 15; 4 + x = 12; 2x = 20
Step1: Solve the first equation
Solve $x + 3=26$ for $x$. Subtract 3 from both sides: $x=26 - 3=23$.
Step2: Solve the second equation
Solve $5x = 15$ for $x$. Divide both sides by 5: $x=\frac{15}{5}=3$.
Step3: Solve the third equation
Solve $4 + x=12$ for $x$. Subtract 4 from both sides: $x=12 - 4 = 8$.
Step4: Solve the fourth equation
Solve $2x=20$ for $x$. Divide both sides by 2: $x=\frac{20}{2}=10$.
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