Question

which chemical reaction involves the most hydrogen atoms?
a hc₂h₃o₂ + nahco₃ → nac₂h₃o₂ + h₂o + co₂
b c₃h₈ + 5o₂ → 4h₂o + 3co₂ + energy
c 6co₂ + 6h₂o + light → c₆h₁₂o₆ + 6o₂
d 10fe + 7o₂ + h₂o → 5fe₂o₃ + h₂

Explanation:

Step1: Count hydrogen atoms in reaction A

In \(HC_{2}H_{3}O_{2}\), there are \(1 + 3=4\) H atoms. In \(NaHCO_{3}\), there is \(1\) H atom. On the product side, in \(H_{2}O\), there are \(2\) H atoms. Total H atoms: \(4 + 1+2=7\)

Step2: Count hydrogen atoms in reaction B

In \(C_{3}H_{8}\), there are \(8\) H atoms. In \(4H_{2}O\), there are \(4\times2 = 8\) H atoms. Total H atoms: \(8+8 = 16\)

Step3: Count hydrogen atoms in reaction C

In \(6H_{2}O\), there are \(6\times2=12\) H atoms. In \(C_{6}H_{12}O_{6}\), there are \(12\) H atoms. Total H atoms: \(12 + 12=24\)

Step4: Count hydrogen atoms in reaction D (assuming it is \(10Fe+7O_{2}+H_{2}O

ightarrow 5Fe_{2}O_{3}+H_{2}\))
In \(H_{2}O\), there are \(2\) H atoms. In \(H_{2}\), there are \(2\) H atoms. Total H atoms: \(2+2 = 4\)

Answer:

C. \(6CO_{2}+6H_{2}O+\text{light}
ightarrow C_{6}H_{12}O_{6}+6O_{2}\)