Question

which atomic orbitals from carbon hybridize to form the bonds in ch₄?

Explanation:

Step1: Determine the electron configuration of carbon

Carbon has an atomic number of 6. Its electron configuration is \(1s^{2}2s^{2}2p^{2}\).

Step2: Consider hybridization in \(CH_{4}\)

In \(CH_{4}\), carbon undergoes \(sp^{3}\) hybridization. The \(2s\) orbital and the three \(2p\) (\(2p_{x}\), \(2p_{y}\), \(2p_{z}\)) orbitals hybridize.

Answer:

C. \(2s, 2p_{x}, 2p_{y}, 2p_{z}\)