Question

when might an objects average velocity be equal to its average speed in two dimensions? (1 point)
if the object moves in a straight line in one direction represented as positive, then the magnitude of average velocity will be equal to the average speed.
if the object does not loop back to its starting position, then the average velocity will be equal to the average speed.
if the object moves in a straight line in one direction represented as positive, then the direction and magnitude of the average velocity will be equal to the average speed.
the objects average velocity will never be equal to its average speed, in magnitude or direction, because average velocity will be negative and average speed will be positive

Explanation:

• Average velocity: \(v_{avg}=\frac{\Delta x}{\Delta t}\), where \(\Delta x\) is the displacement (a vector quantity, which is the straight - line distance from the initial to the final position with direction) and \(\Delta t\) is the time interval.
• Average speed: \(s_{avg}=\frac{d}{\Delta t}\), where \(d\) is the total distance traveled (a scalar quantity).
• If an object moves in a straight line in one direction:
• The displacement \(\Delta x\) is equal to the distance \(d\) traveled.
• The direction of velocity is the same as the direction of motion (positive in this case, since we assume the direction of motion as positive).
• For other cases:
• If the object does not loop back but moves in a non - straight path (e.g., a curved path in 2D), \(d

eq\Delta x\), so \(v_{avg}
eq s_{avg}\).

• Velocity is a vector and speed is a scalar. But when \(d = \Delta x\) (straight - line, one - direction motion), \(|v_{avg}|=s_{avg}\) and the direction of \(v_{avg}\) is positive (same as the assumed positive direction of motion).

Answer:

If the object moves in a straight line in one direction represented as positive, then the magnitude of average velocity will be equal to the average speed.