Question

when h₂so₄ is mixed with naoh, an acid - base neutralization reaction proceeds, and ______ is one of the products. hint: write the balanced equation before attempting to select an answer. h₃o na₂so₄ na₂s naso₃

Explanation:

Step1: Write the unbalanced equation

The reaction between \(H_2SO_4\) (sulfuric acid) and \(NaOH\) (sodium hydroxide) is an acid - base reaction. The general form of an acid - base reaction is \(acid+base
ightarrow salt + water\). So, the unbalanced equation is \(H_2SO_4+NaOH
ightarrow Na_2SO_4 + H_2O\)

Step2: Balance the equation

• Balance the \(Na\) atoms: There are \(2\) \(Na\) atoms on the right - hand side (\(Na_2SO_4\)) and \(1\) \(Na\) atom on the left - hand side (\(NaOH\)). So, put a coefficient of \(2\) in front of \(NaOH\). The equation becomes \(H_2SO_4 + 2NaOH

ightarrow Na_2SO_4+H_2O\)

• Balance the \(H\) and \(O\) atoms: On the left - hand side, we have \(H_2SO_4\) (\(2\) \(H\) atoms) and \(2NaOH\) (\(2\) \(H\) atoms), so a total of \(4\) \(H\) atoms. On the right - hand side, \(H_2O\) has \(2\) \(H\) atoms. Put a coefficient of \(2\) in front of \(H_2O\). The balanced equation is \(H_2SO_4+2NaOH = Na_2SO_4 + 2H_2O\)

Answer:

\(Na_2SO_4\)