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what is the volume of this figure? 2 ft. 4 ft. 2 ft. 6 ft. 4 ft. 3 ft. …

Question

what is the volume of this figure?
2 ft.
4 ft. 2 ft.
6 ft. 4 ft.
3 ft.
6 ft.
blank cubic feet
submit

Explanation:

Step1: Calculate volume of large rectangle

The large rectangle (if there were no indentation) would have dimensions \( 6 \, \text{ft} \times 6 \, \text{ft} \times 3 \, \text{ft} \). Volume formula is \( V = l \times w \times h \), so \( V_{\text{large}} = 6 \times 6 \times 3 = 108 \, \text{cubic feet} \).

Step2: Calculate volume of the indentation

The indentation is a rectangular prism with dimensions \( 4 \, \text{ft} \times (6 - 2 - 2) \, \text{ft} \times 3 \, \text{ft} \). First, the width of the indentation: \( 6 - 2 - 2 = 2 \, \text{ft} \). Then volume: \( V_{\text{indent}} = 4 \times 2 \times 3 = 24 \, \text{cubic feet} \).

Step3: Subtract indentation from large volume

The volume of the figure is \( V_{\text{large}} - V_{\text{indent}} = 108 - 24 = 84 \, \text{cubic feet} \). Alternatively, we can calculate the volume by adding the volumes of the three rectangular prisms: left (\( 2 \times 6 \times 3 \)), middle (\( 2 \times (6 - 4) \times 3 \)), right (\( 2 \times 4 \times 3 \)). Left: \( 2 \times 6 \times 3 = 36 \), middle: \( 2 \times 2 \times 3 = 12 \), right: \( 2 \times 4 \times 3 = 24 \). Sum: \( 36 + 12 + 24 = 72 \)? Wait, no, earlier method was wrong. Wait, let's re - examine the figure.

Wait, correct approach: The figure can be divided into three parts. Left part: width 2 ft, height 6 ft, depth 3 ft: \( 2 \times 6 \times 3 = 36 \). Middle part: width (6 - 2 - 2)=2 ft, height (6 - 4)=2 ft, depth 3 ft: \( 2 \times 2 \times 3 = 12 \). Right part: width 2 ft, height 4 ft, depth 3 ft: \( 2 \times 4 \times 3 = 24 \). Sum: \( 36+12 + 24=72 \)? Wait, no, my first method was incorrect. Wait, let's look at the height. Wait, the total height is 6 ft, the right part has height 4 ft, the middle indentation: the vertical length of the indentation is 4 ft? Wait, no, the figure's height is 6 ft, the right block has height 4 ft, so the middle block (the indentation's vertical part) has height \( 6 - 4 = 2 \) ft. Wait, maybe better to use the first method correctly. The large outer dimensions: length 6, width 6, depth 3. But the indentation is in the middle, with height 4 ft? Wait, no, the depth is 3 ft (the front - back dimension). Let's re - analyze the figure.

Alternative approach: The figure is a 3D shape with length 6, depth 3, and we can think of the height as varying. The left column: width 2, height 6, depth 3: \( 2\times6\times3 = 36 \). The middle column: width (6 - 2 - 2)=2, height (6 - 4)=2, depth 3: \( 2\times2\times3 = 12 \). The right column: width 2, height 4, depth 3: \( 2\times4\times3 = 24 \). Sum: \( 36 + 12+24 = 72 \)? Wait, that can't be. Wait, maybe the depth is 3 ft, length 6 ft, and the height: left block height 6, middle block height (6 - 4)=2, right block height 4. Wait, no, the depth is 3, so each block's volume is width × height × depth.

Wait, another way: The overall dimensions if we consider the base as 6x3 (length x depth), and height varying. The total volume can be calculated as the area of the front face times depth. The front face area: area of the large rectangle (6x6) minus the area of the indentation (4x(6 - 2 - 2)) = 36 - 8 = 28? No, front face: left rectangle (2x6), middle rectangle (2x(6 - 4)), right rectangle (2x4). So front area: (2×6)+(2×2)+(2×4)=12 + 4+8 = 24. Then volume is front area × depth (3): 24×3 = 72? Wait, I think I made a mistake earlier. Let's check the dimensions again.

Looking at the figure: The total length (horizontal) is 6 ft, depth (into the page) is 3 ft. The left block: width 2 ft, height 6 ft, depth 3 ft: volume 2×6×3 = 36. The middle block: the indentatio…

Answer:

72