Question

what is the volume of a cylinder with a height of 9.2 ft and a base with a radius of 3.9 ft, to the nearest tenth of a cubic foot? answer attempt 2 out of 2 439.7 ft³ submit answer

Explanation:

Step1: Recall the formula for the volume of a cylinder

The volume \( V \) of a cylinder is given by the formula \( V=\pi r^{2}h \), where \( r \) is the radius of the base and \( h \) is the height of the cylinder.

Step2: Substitute the given values into the formula

We are given that \( r = 3.9\space\text{ft} \) and \( h=9.2\space\text{ft} \). Substituting these values into the formula, we get:
\( V=\pi\times(3.9)^{2}\times9.2 \)
First, calculate \( (3.9)^{2}=3.9\times3.9 = 15.21 \)
Then, multiply this by \( 9.2 \): \( 15.21\times9.2=139.932 \)
Now, multiply by \( \pi \) (using \( \pi\approx3.14159 \)): \( V\approx3.14159\times139.932 \)
\( V\approx3.14159\times139.932\approx439.7 \) (rounded to the nearest tenth)

Answer:

\( 439.7 \) cubic feet