Question

if $m^2 = 16$, what are the values of $m$?

Explanation:

Step1: Recall square root property

To solve \( m^2 = 16 \), we use the property that if \( x^2 = a \) (where \( a\geq0 \)), then \( x=\pm\sqrt{a} \).

Step2: Apply the property

Here, \( a = 16 \), so \( m=\pm\sqrt{16} \).
Since \( \sqrt{16}=4 \), we have \( m = 4 \) or \( m=- 4 \).

Answer:

The values of \( m \) are \( 4 \) and \( - 4 \).