Question

what is the value of n to the nearest whole number? 10 13 18 21 law of cosines: ( a^2 = b^2 + c^2 - 2bccos(a) )

Explanation:

Step1: Substitute values into the formula

Given \(a^{2}=b^{2}+c^{2}-2bc\cos(A)\), here \(b = 12\), \(c = 5\), \(A=90^{\circ}\), \(\cos(90^{\circ})=0\). So \(a^{2}=12^{2}+5^{2}-2\times12\times5\times0\).

Step2: Calculate \(a^{2}\)

\(a^{2}=144 + 25-0=169\).

Step3: Find \(a\)

Take the square root of \(a^{2}\), \(a=\sqrt{169}=13\).

Answer:

13