Question

what is the total number of oxygen atoms on the right - hand side of this chemical equation?
8al(s)+3nano3(aq)+5naoh(aq)+18h2o(l)→8naal(oh)4(aq)+3nh3(g)

Explanation:

Step1: Analyze the oxygen atoms in \(NaAl(OH)_4\)

In \(NaAl(OH)_4\), there are 4 oxygen atoms per formula unit. There are 8 formula units of \(NaAl(OH)_4\). So the number of oxygen atoms from \(NaAl(OH)_4\) is \(8\times4 = 32\).

Step2: Analyze the oxygen atoms in \(NH_3\)

In \(NH_3\), there are 0 oxygen atoms.

Answer:

32