Question

what is the sum of 2 of the interior angles of a regular pentagon? answer attempt 1 out of 2

Explanation:

Step1: Find sum of interior angles

The formula for the sum of interior angles of a polygon is $(n - 2)\times180^\circ$, where $n$ is the number of sides. For a pentagon, $n = 5$. So sum is $(5 - 2)\times180^\circ= 3\times180^\circ = 540^\circ$.

Step2: Find one interior angle

In a regular pentagon, all interior angles are equal. So one interior angle is $\frac{540^\circ}{5}= 108^\circ$.

Step3: Find sum of 2 interior angles

Multiply one interior angle by 2: $2\times108^\circ = 216^\circ$.

Answer:

$216^\circ$