what are the sides of △mno listed from shortest to longest?
o a. overline {mo},overline {no},overline {mn}
o b. overline {mn},overline {mo},overline {no}
o c. overline {mn},overline {no},overline {mo}
o d. overline {no},overline {mo},overline {mn}

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# Explanation:
## Step1: Find the measure of angle $N$
In $\triangle MNO$, we know that the sum of angles in a triangle is $180^{\circ}$.
Let $\angle M = 61^{\circ}$, assume we can find $\angle N$ using parallel - line properties (the transversal and parallel lines give us that $\angle N=54^{\circ}$). Then $\angle O=180^{\circ}-\angle M - \angle N=180^{\circ}-61^{\circ}-54^{\circ}=65^{\circ}$.
## Step2: Use the angle - side relationship
In a triangle, the side opposite the smaller angle is shorter.
Since $\angle N = 54^{\circ}$, $\angle M=61^{\circ}$, $\angle O = 65^{\circ}$, and the side opposite $\angle N$ is $MO$, the side opposite $\angle M$ is $NO$, the side opposite $\angle O$ is $MN$.
Because $54^{\circ}<61^{\circ}<65^{\circ}$, then $MO<NO<MN$ (by the rule that in a triangle $a/sinA=b/sinB = c/sinC$, and when $A < B < C$, $a < b < c$ where $a,b,c$ are sides opposite to angles $A,B,C$ respectively)

# Answer:
A. $\overline{MO},\overline{NO},\overline{MN}$

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Explanation:

Step1: Find the measure of angle \(N\)

Step2: Use the angle - side relationship

Answer: