Question

what is the quantity of work done when a crane lifts a 100 - n block from 2 m above the ground to 6 m above the ground? 100 j 200 j 400 j 600 j

Explanation:

Step1: Calculate the displacement

The displacement \(d\) is the change in height. The block is lifted from \(2\) m to \(6\) m, so \(d=6 - 2=4\) m.

Step2: Use the work - formula

The formula for work \(W\) is \(W = F\times d\), where \(F = 100\) N (force) and \(d = 4\) m (displacement). Substitute the values: \(W=100\times4\).

Answer:

\(400\) J (since \(100\times4 = 400\), so the answer is \(400\) J which corresponds to the option \(400\) J)