Question

what is $(a^2 - 11) + (3a^2 - 4a + 6)$? (1 point)
\bigcirc $3a^2 - 4a - 5$
\bigcirc $-4a^2 + 4a + 5$
\bigcirc $4a^2 - 4a - 5$
\bigcirc $-5$

Explanation:

Step1: Remove parentheses

To add the two polynomials, we first remove the parentheses. The expression becomes \(a^{2}-11 + 3a^{2}-4a + 6\).

Step2: Combine like terms

For the \(a^{2}\) terms: \(a^{2}+3a^{2}=4a^{2}\).
For the constant terms: \(- 11+6=-5\).
The \(a\) term remains as \(-4a\) since there is no other like term to combine with it.
Putting it all together, we get \(4a^{2}-4a - 5\).

Answer:

\(4a^{2}-4a - 5\) (corresponding to the option " \(4a^{2}-4a - 5\)")