Question

what is the percent o in n₂o?
(n = 14.01 g/mol, o = 16.00 g/mol)
? % o

Explanation:

Step1: Calculate molar mass of N₂O

Molar mass of N₂O = (2 × molar mass of N) + (1 × molar mass of O) = (2 × 14.01 g/mol) + (1 × 16.00 g/mol) = 28.02 g/mol + 16.00 g/mol = 44.02 g/mol

Step2: Calculate mass of O in N₂O

Mass of O in N₂O = 1 × 16.00 g/mol = 16.00 g/mol

Step3: Calculate percent composition of O

Percent O = (Mass of O / Molar mass of N₂O) × 100% = ($\frac{16.00}{44.02}$) × 100% ≈ 36.35%

Answer:

36.35%