Question

what operation is needed to eliminate the 2ab from both sides? pythagorean theorem a = a1 + a2 + a3 + a4 + a5 (a+b)² = a1 + a2 + a3 + a4 + a5 (a+b)² = a1 + a2 + a3 + a4 + c² (a+b)² = ½ab + ½ab ½ab + ½ab + c² (a+b)(a+b) = 2ab + c² a² + 2ab + b² = 2ab + c² add 2ab add a² subtract b² subtract 2ab

Explanation:

Step1: Analyze the equation

We have the equation \(a^{2}+2ab + b^{2}=2ab + c^{2}\). To eliminate \(2ab\) from both sides, we need to perform an operation that cancels out \(2ab\) on each side.

Step2: Determine the operation

Subtracting \(2ab\) from both sides of the equation will give us \(a^{2}+2ab + b^{2}- 2ab=2ab + c^{2}-2ab\), which simplifies to \(a^{2}+b^{2}=c^{2}\) (the Pythagorean theorem). So the operation needed is to subtract \(2ab\).

Answer:

subtract 2ab