QUESTION IMAGE
Question
what is one of the solutions to the following system?
\\(\
$$\begin{cases} y - 3 = x \\\\ x^2 - 6x + 13 = y \\end{cases}$$
\\)
\\(\bigcirc\\) \\((-5, 2)\\)
\\(\bigcirc\\) \\((-2, 1)\\)
\\(\bigcirc\\) \\((2, 5)\\)
\\(\bigcirc\\) \\((8, 5)\\)
Express y in terms of x
$$
LATEXBLOCK0
$$
Substitute and set up the quadratic equation
$$
LATEXBLOCK1
$$
Solve for x and find corresponding y values
$$
LATEXBLOCK2
$$
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- (-5, 2)
- (-2, 1)
- (2, 5) (Correct answer)
- (8, 5)