Question

what number has 8 ten thousands, 5 fewer thousands than ten thousands, 6 more hundreds than thousands, 6 more tens than thousands, and the same number of ones as thousands?

Explanation:

Step1: Determine ten - thousands place

The number has 8 ten - thousands. So the digit in the ten - thousands place is 8.

Step2: Determine thousands place

It has 5 fewer thousands than ten - thousands. Since ten - thousands digit is 8, the thousands digit is $8 - 5=3$.

Step3: Determine hundreds place

It has 6 more hundreds than thousands. Since thousands digit is 3, the hundreds digit is $3 + 6 = 9$.

Step4: Determine tens place

It has 6 more tens than thousands. Since thousands digit is 3, the tens digit is $3+6 = 9$.

Step5: Determine ones place

It has the same number of ones as thousands. Since thousands digit is 3, the ones digit is 3.

Now, we write the number by placing the digits in their respective places: ten - thousands (8), thousands (3), hundreds (9), tens (9), ones (3). So the number is 83993.

Answer:

83993