Question

what is ( moverarc{qt} )?
( moverarc{qt} ) = ( square )°

Explanation:

Step1: Recall the total degrees in a circle

A full - circle has \(360^{\circ}\).

Step2: Set up the equation

Let \(m\overarc{QT}=x\). Then \(55^{\circ}+55^{\circ}+105^{\circ}+x = 360^{\circ}\).

Step3: Simplify the left - hand side

\(55 + 55+105+x=(55 + 55)+105+x=110 + 105+x=215+x\).

Step4: Solve for \(x\)

Subtract \(215^{\circ}\) from both sides of the equation \(215+x = 360\). So \(x=360 - 215\).

Answer:

\(145\)