Question

what is the molarity of a solution if you add 18.18 g of sodium hydroxide to water to make 468 ml of a sodium hydroxide solution? answer to thousandth place. ( m_{naoh}=39.997g/mol )

Explanation:

Step1: Calculate the number of moles of NaOH

The formula for the number of moles \(n=\frac{m}{M}\), where \(m = 18.18\space g\) (mass of NaOH) and \(M=39.997\space g/mol\) (molar mass of NaOH).
\(n=\frac{18.18}{39.997}\approx0.4545\space mol\)

Step2: Convert the volume of the solution to liters

The volume \(V = 468\space mL\). Since \(1\space L=1000\space mL\), then \(V=\frac{468}{1000}=0.468\space L\)

Step3: Calculate the molarity

The formula for molarity \(M=\frac{n}{V}\), where \(n = 0.4545\space mol\) and \(V = 0.468\space L\)
\(M=\frac{0.4545}{0.468}\approx0.971\space mol/L\)

Answer:

\(0.971\space mol/L\)