Question

what is the molarity of the resulting solution when 300. ml of a 0.400 m solution is diluted to 800. ml? 0.109 m 0.150 m 1.07 m 1.47 m

Explanation:

Step1: Use the dilution formula

The dilution formula is \(M_1V_1 = M_2V_2\), where \(M_1\) is the initial molarity, \(V_1\) is the initial volume, \(M_2\) is the final molarity, and \(V_2\) is the final volume.
Given \(M_1 = 0.400\space M\), \(V_1=300\space mL\), and \(V_2 = 800\space mL\). We need to find \(M_2\).

Step2: Rearrange the formula to solve for \(M_2\)

From \(M_1V_1 = M_2V_2\), we can solve for \(M_2\) as \(M_2=\frac{M_1V_1}{V_2}\).
Substitute the values: \(M_2=\frac{0.400\space M\times300\space mL}{800\space mL}\)

$$M_2=\frac{120}{800}\space M = 0.150\space M$$

Answer:

B. \(0.150\space M\)