Question

what is the missing particle?
133 54 xe* → ? + 0 0 γ
133 53 xe 133 54 xe 133 53 i

Explanation:

Step1: Analyze mass number conservation

In nuclear reactions, the sum of mass numbers on both sides must be equal. The mass number of \(^{133}_{54}\text{Xe}^*\) is \(133\), and for \(\gamma\) (gamma - ray) it is \(0\). Let the mass number of the missing particle be \(A\). Then \(A+0 = 133\), so \(A = 133\).

Step2: Analyze atomic number conservation

The sum of atomic numbers on both sides must be equal. The atomic number of \(^{133}_{54}\text{Xe}^*\) is \(54\), and for \(\gamma\) it is \(0\). Let the atomic number of the missing particle be \(Z\). Then \(Z + 0=54\), so \(Z = 54\).

Answer:

\(^{133}_{54}\text{Xe}\)