Question

what is the mass of 3.01 x 10^{23} molecules of c_{6}h_{12}o_{6}? (1 mol c_{6}h_{12}o_{6} = 180.18 g) (1 mol c_{6}h_{12}o_{6} = 6.02 x 10^{23} molecules) ? g c_{6}h_{12}o_{6}

Explanation:

Step1: Calculate the number of moles

Use the formula \(n=\frac{N}{N_{A}}\), where \(N = 3.01\times10^{23}\) molecules and \(N_{A}=6.02\times 10^{23}\text{ molecules/mol}\).
\(n=\frac{3.01\times 10^{23}}{6.02\times 10^{23}\text{ molecules/mol}} = 0.5\text{ mol}\)

Step2: Calculate the mass

Use the formula \(m=n\times M\), where \(n = 0.5\text{ mol}\) and \(M = 180.18\text{ g/mol}\)
\(m=0.5\text{ mol}\times180.18\text{ g/mol}=90.09\text{ g}\)

Answer:

\(90.09\)