Question

what is the kinetic energy of a 478 kg object that is moving with a speed of 15 m/s?

Explanation:

Step1: Write the formula for kinetic energy

The formula for kinetic energy is \( KE=\frac{1}{2}mv^{2} \), where \( m \) is the mass of the object and \( v \) is the speed of the object.

Step2: Substitute the given values into the formula

Given \( m = 478\space kg \) and \( v=15\space m/s \). Substitute these values into the formula: \( KE=\frac{1}{2}\times478\times(15)^{2} \).
First, calculate \( (15)^{2}=225 \). Then, \( \frac{1}{2}\times478 = 239 \).

Step3: Calculate the kinetic energy

Multiply \( 239\times225\). \( 239\times225=(200 + 39)\times225=200\times225+39\times225=45000+8775 = 53775\space J \)

Answer:

The kinetic energy of the object is \( 53775\space J \)