Question

b. what is isabellas velocity from t=3 to t=6?

Explanation:

Step1: Recall velocity formula

Velocity $v=\frac{\Delta x}{\Delta t}$, where $\Delta x$ is change in position and $\Delta t$ is change in time. But since no information about position - change is given, we assume we need to use the slope of the position - time graph (if available). Here we assume the general form. $\Delta t=t_2 - t_1$, with $t_1 = 3$ and $t_2=6$, so $\Delta t=6 - 3=3$. Without information about $\Delta x$, we can't calculate a numerical value. But if we assume a linear - motion situation and have a position function $x(t)$, the average velocity $v_{avg}=\frac{x(6)-x(3)}{6 - 3}$.

Step2: Since no data is given

We can only state the general formula for average velocity. The average velocity from $t = 3$ to $t = 6$ is given by $v=\frac{x(6)-x(3)}{3}$, where $x(t)$ is the position function of Isabella's motion.

Answer:

The average velocity $v=\frac{x(6)-x(3)}{3}$, where $x(t)$ is the position function of Isabella's motion.