Question

1. what is the full electron configuration for oxygen? a. 1s²2p⁴ c. 1s²2s²2p⁴ b. 2p⁶ d. 2sp⁸

Explanation:

Oxygen has an atomic number of 8, meaning it has 8 electrons. Electrons fill orbitals in a specific order: 1s first (holds 2 electrons), then 2s (holds 2 electrons), and then 2p (holds up to 6 electrons). For oxygen, after filling 1s² and 2s², there are 4 electrons left for the 2p orbital. So the electron configuration is \(1s^{2}2s^{2}2p^{4}\). Option a is missing the 2s² part. Option b (\(2p^{6}\)) would imply 6 electrons in 2p only which is incorrect as we need to account for 1s and 2s. Option d (\(2sp^{8}\)) is an incorrect notation (there's no 2sp orbital combination in standard electron - configuration notation).

Answer:

C. \(1s^{2}2s^{2}2p^{4}\)