Question

what is the formula for lead(ii) chloride? what is the formula for cobalt(ii) iodide? what is the formula for nickel(ii) fluoride?

Explanation:

Step1: Determine ion charges

Lead(II) has a charge of $Pb^{2 +}$, chloride has a charge of $Cl^{-}$. To balance the charges, we need 2 chloride ions for 1 lead - ion.

Step2: Write the formula

The formula for lead(II) chloride is $PbCl_{2}$.

Step3: Determine ion charges for cobalt(II) iodide

Cobalt(II) has a charge of $Co^{2+}$, iodide has a charge of $I^{-}$. To balance the charges, we need 2 iodide ions for 1 cobalt - ion.

Step4: Write the formula

The formula for cobalt(II) iodide is $CoI_{2}$.

Step5: Determine ion charges for nickel(II) fluoride

Nickel(II) has a charge of $Ni^{2+}$, fluoride has a charge of $F^{-}$. To balance the charges, we need 2 fluoride ions for 1 nickel - ion.

Step6: Write the formula

The formula for nickel(II) fluoride is $NiF_{2}$.

Answer:

Lead(II) chloride: $PbCl_{2}$
Cobalt(II) iodide: $CoI_{2}$
Nickel(II) fluoride: $NiF_{2}$