Question

what is the formula for copper(ii) phosphate? capitalization and punctuation count. formula: cu₃(po₄)₂ how many atoms of phosphorus are in 5.40 mol of copper(ii) phosphate? number of p atoms =

Explanation:

Step1: Determine P atoms per formula unit

In $Cu_3(PO_4)_2$, there are 2 P atoms per formula - unit.

Step2: Calculate moles of P

For 5.40 mol of $Cu_3(PO_4)_2$, moles of P is $n = 5.40\ mol\times2=10.8\ mol$.

Step3: Use Avogadro's number

Avogadro's number $N_A = 6.022\times 10^{23}\ atoms/mol$. Number of P atoms $N=n\times N_A$.
$N = 10.8\ mol\times6.022\times 10^{23}\ atoms/mol=6.50376\times 10^{24}$ atoms.

Answer:

$6.50\times 10^{24}$