Question

3 what will the follo ng program print when run?
soda_ounces = 8
soda_liters = 7
if soda_ounces >= 8:
print(\crackle\)
if soda_ounces < 7:
print(\babble\)
if soda_liters > soda_ounces:
print(\fizz\)
if soda_liters <= soda_ounces:
print(\pop\)
if soda_ounces != soda_liters:
print(\fizzle\)
a. babble
crackle
pop
b. crackle
pop
fizz
c. fizz
pop
fizzle
d. crackle
pop
fizzle

Explanation:

Step1: Check first condition

soda_ounces = 8, 8 >= 8 is True, so "crackle" is printed.

Step2: Check second condition

soda_ounces = 8, 8 < 7 is False, so "babble" is not printed.

Step3: Check third condition

soda_liters = 7, soda_ounces = 8, 7 > 8 is False, so "fizz" is not printed.

Step4: Check fourth condition

soda_liters = 7, soda_ounces = 8, 7 <= 8 is True, so "pop" is printed.

Step5: Check fifth condition

soda_ounces = 8, soda_liters = 7, 8 != 7 is True, so "fizzle" is printed.

Answer:

D. crackle pop fizzle