Question

what is the final volume of the diluted solution when 25.0 ml of 5.0 m nacl is diluted to 2.0 m? ? ml

Explanation:

Step1: Recall dilution formula

The dilution formula is \( M_1V_1 = M_2V_2 \), where \( M_1 \) is the initial molarity, \( V_1 \) is the initial volume, \( M_2 \) is the final molarity, and \( V_2 \) is the final volume.

Step2: Identify known values

We know \( M_1 = 5.0 \, M \), \( V_1 = 25.0 \, mL \), and \( M_2 = 2.0 \, M \). We need to find \( V_2 \).

Step3: Rearrange formula to solve for \( V_2 \)

From \( M_1V_1 = M_2V_2 \), we get \( V_2=\frac{M_1V_1}{M_2} \).

Step4: Substitute values into the formula

Substitute \( M_1 = 5.0 \, M \), \( V_1 = 25.0 \, mL \), and \( M_2 = 2.0 \, M \) into the formula: \( V_2=\frac{5.0 \, M\times25.0 \, mL}{2.0 \, M} \).

Step5: Calculate the value

First, calculate the numerator: \( 5.0\times25.0 = 125 \). Then divide by the denominator: \( \frac{125}{2.0}=62.5 \, mL \).

Answer:

62.5