Question

what is the electric potential energy of an electron at the negative end of the cable, relative to the positive end of the cable? in other words, assume that the electric potential of the positive terminal is 0 v and that of the negative terminal is - 12 v. recall that e = 1.60×10^(-19) c. enter your answer in joules. u_e = j

Explanation:

Step1: Identify the formula

The formula for electric - potential energy is $U_E = qV$, where $q$ is the charge and $V$ is the electric potential.

Step2: Determine the values of $q$ and $V$

The charge of an electron $q=- 1.60\times10^{-19}\ C$ (negative because it's an electron), and the potential difference $V = V_{negative}-V_{positive}=-12\ V - 0\ V=-12\ V$.

Step3: Calculate the electric - potential energy

$U_E=qV=(-1.60\times 10^{-19}\ C)\times(-12\ V)=1.92\times10^{-18}\ J$

Answer:

$1.92\times 10^{-18}$