Question

1. what is the distance between j (-6, -2) and h (2.5, -2)?

Explanation:

Step1: Identify the formula for distance

The distance formula between two points \((x_1,y_1)\) and \((x_2,y_2)\) is \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). Here, \(y_1=y_2=-2\), so the formula simplifies to \(d=\vert x_2 - x_1\vert\).

Step2: Substitute the \(x -\) values

Substitute \(x_1=-6\) and \(x_2 = 2.5\) into \(d=\vert x_2 - x_1\vert\). Then \(d=\vert2.5-(-6)\vert=\vert2.5 + 6\vert\).

Step3: Calculate the absolute - value

\(\vert2.5+6\vert=\vert8.5\vert = 8.5\)

Answer:

\(8.5\)