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Question
what is cot(∠a)? reduce fractional answers to lowest terms. triangle with right angle at c, ac=12, cb=5, ab=13
Step1: Recall cotangent definition
In a right triangle, $\cot(\theta) = \frac{\text{adjacent}}{\text{opposite}}$ to angle $\theta$. For $\angle A$, adjacent side is $AC$ and opposite side is $BC$.
Given $AC = 12$, $BC = 5$.
Step2: Calculate $\cot(\angle A)$
Using the definition, $\cot(\angle A) = \frac{AC}{BC} = \frac{12}{5}$.
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$\frac{12}{5}$