Question

what are the coordinates of point l after △jkl is reflected across the x-axis? l (\square, ?)

Explanation:

Step1: Recall reflection over x-axis rule

The rule for reflecting a point \((x, y)\) across the \(x\)-axis is \((x, -y)\), which means the \(x\)-coordinate remains the same, and the \(y\)-coordinate is multiplied by \(-1\).

Step2: Identify original coordinates of L

From the graph, the coordinates of point \(L\) are \((2, -4)\).

Step3: Apply reflection rule

Using the reflection rule across the \(x\)-axis, substitute \(x = 2\) and \(y = -4\) into \((x, -y)\). So, the \(x\)-coordinate stays \(2\), and the \(y\)-coordinate becomes \(-(-4)=4\). Thus, the coordinates of \(L'\) are \((2, 4)\).

Answer:

\(L'(2, 4)\)