Question

what is the concentration in m when 100. g of nacl is made to a final volume of 2.00 l? the molar mass of nacl is 58.44 g/mol. first we get the moles 1 mol (2 g)(---------) = 3 mol 4 g then we divide by the volume 5 mol (---------) = 6 m 7 l a. 0 b. 1 c. 2 d. 3 e. 4 f. 5 g. 6 h. 234 i. 58.44 j. 100. k. 1.71 l. 0.856 m. 10.0

Explanation:

Step1: Calculate moles of NaCl

Moles = mass / molar mass. Mass (\(m\)) = \(100. g\), molar mass (\(M\)) = \(58.44 g/mol\).
\(n=\frac{m}{M}=\frac{100. g}{58.44 g/mol}\approx1.71 mol\)
So, blank 1: K, blank 2: J, blank 3: K, blank 4: I.

Step2: Calculate molarity

Molarity (\(M\)) = moles / volume. Moles (\(n\)) = \(1.71 mol\), volume (\(V\)) = \(2.00 L\)
\(M=\frac{n}{V}=\frac{1.71 mol}{2.00 L}=0.856 M\)
So, blank 5: K, blank 7: C, blank 6: L.

Answer:

1: K, 2: J, 3: K, 4: I, 5: K, 6: L, 7: C