Question

what is the bond order in c₂⁺? 0 1.5 2.5 2.0

Explanation:

Step1: Write the molecular orbital configuration

Carbon has 6 electrons. \(C_{2}^{+}\) has \(6 + 6-1=11\) electrons. The molecular orbital configuration is \(\sigma1s^{2}\sigma^{*}1s^{2}\sigma2s^{2}\sigma^{*}2s^{2}\pi2p_{x}^{2}\pi2p_{y}^{2}\sigma2p_{z}^{1}\)

Step2: Calculate the bond order

The formula for bond order is \(BO=\frac{N_{b}-N_{a}}{2}\), where \(N_{b}\) is the number of bonding electrons and \(N_{a}\) is the number of antibonding electrons. Here \(N_{b} = 7\) and \(N_{a}=4\). So \(BO=\frac{7 - 4}{2}=\frac{3}{2}=1.5\)

Answer:

1.5