Question

what is the balanced equation for this reaction? hclo₄ + mg(oh)₂ →

Explanation:

Step1: Analyze the reaction type

This is an acid - base neutralization reaction. The acid \(HClO_4\) reacts with the base \(Mg(OH)_2\) to form a salt \(Mg(ClO_4)_2\) and water \(H_2O\).

Step2: Balance the equation

• For \(ClO_4\) group: There is \(1\) \(ClO_4\) in \(HClO_4\) and \(2\) \(ClO_4\) in \(Mg(ClO_4)_2\). So, we need \(2\) moles of \(HClO_4\).
• For \(Mg\): There is \(1\) \(Mg\) in \(Mg(OH)_2\) and \(1\) \(Mg\) in \(Mg(ClO_4)_2\).
• For \(H\) and \(O\): After putting \(2\) in front of \(HClO_4\), we have \(2H^+\) from \(HClO_4\) and \(2OH^-\) from \(Mg(OH)_2\). The total number of \(H\) atoms is \(2 + 2=4\) and \(O\) atoms (from \(OH\) groups) is \(2\). The salt \(Mg(ClO_4)_2\) doesn't contribute to \(H\) and \(O\) (except from \(ClO_4\) which is already balanced). The water formed: from \(H^+\) and \(OH^-\) combination. \(4H\) and \(2O\) gives \(2H_2O\).

The balanced equation is \(2HClO_4+Mg(OH)_2 = Mg(ClO_4)_2 + 2H_2O\)

Answer:

\(2HClO_4+Mg(OH)_2 = Mg(ClO_4)_2 + 2H_2O\)