Question

1. what is the acceleration of the object below?

given:
final velocity = 34 meters per second squared north
initial velocity = 10 meters per second squared north
final time = 12 seconds
initial time = 4 seconds
44 meters per second squared north
3 meters per second squared north
16 meters per second squared north
8 meters per second squared north
clear all

Explanation:

Step1: Identify the formula for acceleration

The formula for acceleration \(a=\frac{v_f - v_i}{t_f - t_i}\), where \(v_f\) is final velocity, \(v_i\) is initial velocity, \(t_f\) is final time, and \(t_i\) is initial time.

Step2: Substitute the given values into the formula

Given \(v_f = 34\ m/s^2\) (north), \(v_i = 10\ m/s^2\) (north), \(t_f=12\ s\), \(t_i = 4\ s\).

$$a=\frac{34 - 10}{12 - 4}$$

Step3: Calculate the numerator and denominator

Numerator: \(34-10 = 24\). Denominator: \(12 - 4=8\).

$$a=\frac{24}{8}$$

Step4: Find the value of acceleration

\(a = 3\ m/s^2\) (north)

Answer:

3 meters per second squared north