Question

what is the acceleration of a 6.4 kg bowling ball if a force of 12 n is applied to it?

Explanation:

Step1: Recall Newton's second law

Newton's second law is \(F = ma\), where \(F\) is force, \(m\) is mass, and \(a\) is acceleration. We need to solve for \(a\), so we can rewrite the formula as \(a=\frac{F}{m}\).

Step2: Substitute the given values

Given \(F = 12\space N\) and \(m=6.4\space kg\). Substitute these into the formula: \(a=\frac{12}{6.4}\).

Step3: Calculate the value

\(a=\frac{12}{6.4}= 1.875\space m/s^{2}\)

Answer:

\(1.875\space m/s^{2}\)