Question

what is the acceleration of a 32 kg object if a 6.75 n force is applied to it?
0.21 m/s²
4.74 m/s²
21.09 m/s²
216.00 m/s²

Explanation:

Step1: Recall Newton's Second Law

Newton's second law states that \( F = ma \), where \( F \) is force, \( m \) is mass, and \( a \) is acceleration. We need to solve for \( a \), so we rearrange the formula to \( a=\frac{F}{m} \).

Step2: Substitute the given values

We know that \( F = 6.75\space N \) and \( m = 32\space kg \). Substituting these into the formula, we get \( a=\frac{6.75}{32} \).

Step3: Calculate the acceleration

Performing the division, \( \frac{6.75}{32}= 0.2109375\approx0.21\space m/s^{2} \).

Answer:

\( 0.21\space m/s^{2} \) (corresponding to the option "0.21 m/s²")