Question

wednesday
use the fact that
123 × 32 = 3936 to
determine the product
of 12.3 × 0.32 = ?
determine the absolute
value for each given
integer.

Explanation:

First Sub - Question (12.3×0.32)

Step1: Analyze decimal places

12.3 has 1 decimal place, 0.32 has 2 decimal places. Total decimal places: \(1 + 2=3\).

Step2: Adjust the known product

Given \(123\times32 = 3936\). For \(12.3\times0.32\), we move the decimal point of 3936 three places to the left.
\(3936\) with decimal point moved three places left is \(3.936\).

The absolute value of an integer is its distance from 0 on the number line. For a non - negative integer \(a\), \(|a|=a\); for a negative integer \(-b\) (where \(b>0\)), \(|-b| = b\).

Answer:

\(12.3\times0.32 = 3.936\)

Second Sub - Question (Absolute Value of Integers)

(Note: Since no specific integers are given, we'll explain the general method. If integers were provided, say for an integer \(n\), the absolute value \(|n|\) is \(n\) if \(n\geq0\) and \(-n\) if \(n < 0\). For example, if the integer is \( - 5\), \(|-5|=5\); if the integer is \(7\), \(|7| = 7\).)