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webwork / fa25 math098-all / hw2.5 euclideancoordinates / 5 previous pr…

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webwork / fa25 math098-all / hw2.5 euclideancoordinates / 5
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hw2.5 euclideancoordinates: proble
(1 point)
consider the two points (5, -3) and (-4, -3). the distance between them is
the x co - ordinate of the midpoint of the line segment that joins them is
the y co - ordinate of the midpoint of the line segment that joins them is:
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Explanation:

Step1: Calculate the distance between two points

Use the distance formula \(d=\sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\). Here \(x_1 = 5,y_1=-3,x_2=-4,y_2 = -3\).
Substitute into the formula: \(d=\sqrt{(-4 - 5)^2+(-3+3)^2}=\sqrt{(-9)^2+0^2}=\sqrt{81}=9\).

Step2: Calculate the x - coordinate of the mid - point

Use the mid - point formula \(M(\frac{x_1 + x_2}{2},\frac{y_1 + y_2}{2})\). For the x - coordinate, \(x=\frac{5+( - 4)}{2}=\frac{1}{2}=0.5\).

Step3: Calculate the y - coordinate of the mid - point

For the y - coordinate, \(y=\frac{-3+( - 3)}{2}=\frac{-6}{2}=-3\).

Answer:

Distance: \(9\); x - coordinate of mid - point: \(0.5\); y - coordinate of mid - point: \(-3\)