Question

water flows through a pipe of radius 0.0250 m at 1.50 m/s. what is the volume flow rate? ? m³/s

Explanation:

Step1: Recall the formula for volume flow rate

The volume flow rate \( Q \) of a fluid flowing through a pipe is given by the product of the cross - sectional area \( A \) of the pipe and the flow speed \( v \), i.e., \( Q = A\times v \). The cross - sectional area of a circular pipe is \( A=\pi r^{2} \), where \( r \) is the radius of the pipe. So the formula for volume flow rate becomes \( Q=\pi r^{2}v \).

Step2: Substitute the given values into the formula

We are given that \( r = 0.0250\space m \) and \( v=1.50\space m/s \). First, calculate the area \( A=\pi\times(0.0250)^{2} \). Then multiply it by the velocity \( v \).

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Answer:

\( 2.95\times 10^{- 3}\space m^{3}/s \) (or approximately \( 0.00295\space m^{3}/s \))