Question

a wagon weighs 1,800 n and is pulled by a horse at 0.40 m. what is the work of the horse?

Explanation:

Step1: Recall the work formula

Work \(W = F\times d\), where \(F\) is the force and \(d\) is the displacement. Here, the weight of the wagon (\(1800N\)) is a distractor. The force applied by the horse is not given directly, but assuming the force is related to moving the wagon (if we assume the force to move it is such that we use the values in a simple \(W = F\times d\) way, and if we take the values as \(F = 1800N\) (wrong assumption, but if we go by the options, maybe a mis - problem setup; or if it's \(F\times d\) where \(F\) is calculated from some other means which is not clear. But if we assume \(W = F\times d\) and \(F = 1800N\) (though in reality, the force to move the wagon is different from its weight, but given the options): \(W=1800\times0.4\)

Step2: Calculate the work

\(W = 1800\times0.4=720J\)

Answer:

720 J