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the volume of a solid right pyramid with a square base is v units³ and …

Question

the volume of a solid right pyramid with a square base is v units³ and the length of the base edge is y units. which expression represents the height of the pyramid? (\frac{3v}{y^2}) units, ((3v - y^2)) units, ((v - 3y^2)) units, (\frac{v}{3y^2}) units

Explanation:

Step1: Recall the volume formula for a square - based pyramid

The volume \( V \) of a right pyramid with a square base is given by the formula \( V=\frac{1}{3}Bh \), where \( B \) is the area of the base and \( h \) is the height of the pyramid. Since the base is a square with side length \( y \), the area of the base \( B = y\times y=y^{2}\). So the volume formula becomes \( V=\frac{1}{3}y^{2}h \).

Step2: Solve the formula for \( h \)

We start with the equation \( V = \frac{1}{3}y^{2}h \). To isolate \( h \), we first multiply both sides of the[SSE onError error]

Answer:

Step1: Recall the volume formula for a square - based pyramid

The volume \( V \) of a right pyramid with a square base is given by the formula \( V=\frac{1}{3}Bh \), where \( B \) is the area of the base and \( h \) is the height of the pyramid. Since the base is a square with side length \( y \), the area of the base \( B = y\times y=y^{2}\). So the volume formula becomes \( V=\frac{1}{3}y^{2}h \).

Step2: Solve the formula for \( h \)

We start with the equation \( V = \frac{1}{3}y^{2}h \). To isolate \( h \), we first multiply both sides of the[SSE onError error]