Question

version - 01 - unit 2: quest 3: speed and velocity
006 10.0 points
ant race 224101
alvin and theodore race across a parking lot 323 cm long. alvin travels at 21.65 cm/s and theodore at 17 cm/s.
when the alvin crosses the finish line, how far behind is theodore?
answer in units of cm. answer in units of cm.

Explanation:

Step1: Calculate the time taken by Alvin to cross the finish line

We use the formula \(t=\frac{d}{v}\), where \(d = 323\) cm (distance of the race) and \(v = 21.65\) cm/s (Alvin's speed).
\(t=\frac{323}{21.65}\)
\(t = 14.9284\) s

Step2: Calculate the distance Theodore covers in the same time

We use the formula \(d=v\times t\), where \(v = 17\) cm/s (Theodore's speed) and \(t = 14.9284\) s (time calculated in Step1)
\(d=17\times14.9284\)
\(d = 253.7828\) cm

Step3: Calculate how far behind Theodore is

We subtract the distance Theodore covers from the total distance of the race. Let \(D\) be the distance Theodore is behind.
\(D=323 - 253.7828\)
\(D = 69.2172\approx69.2\) cm

Answer:

\(69.2\) cm