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Question
- z varies inversely with x and directly with y. when x = 6 and y = 2, z = 5. what is the value of z when x = 4 and y = 9? options: \\(\frac{135}{4}\\), \\(\frac{5}{27}\\), 60, \\(\frac{20}{9}\\)
Step1: Define variation formula
$z = k\frac{y}{x}$ (k=constant)
Step2: Calculate k
$5 = k\frac{2}{6} \Rightarrow k = 5\times3 = 15$
Step3: Find z at x=4,y=9
$z = 15\times\frac{9}{4} = \frac{135}{4}$
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$\frac{135}{4}$